What is (\partial)/(\partial y)(y^2sin(x)) ?

The answer to (\partial)/(\partial y)(y^2sin(x)) is 2ysin(x)

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(\partial)/(\partial y)(y^2sin(x))

\frac{\partial}{\partial y} (y^{2} sin (x))

2 y sin (x)

Solution steps

\frac{\partial}{\partial y} (y^{2} sin (x))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x) \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= sin (x) \cdot 2 y^{2 - 1}

Simplify

= 2 y sin (x)

f (x) = \frac{1}{x - 1}, at x = 2

\frac{1}{s ( s + 8 )}

\int x^{x} (1 + ln (x)) d x

\frac{x ^{4} + 9}{x ^{2}}

\frac{d x}{d t} = 2 (2 x t)

What is (\partial)/(\partial y)(y^2sin(x)) ?
The answer to (\partial)/(\partial y)(y^2sin(x)) is 2ysin(x)