What is the tangent of f(x)= 1/(x-1),\at x=2 ?

The tangent of f(x)= 1/(x-1),\at x=2 is y=-x+3

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tangent of f(x)= 1/(x-1),\at x=2

tangent of

f (x) = \frac{1}{x - 1}, at x = 2

y = - x + 3

Solution steps

Find the tangent point:

(2, 1)

Find the slope of

f (x) = \frac{1}{x - 1} : \frac{df ( x )}{d x} = - \frac{1}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(2, 1) : y = - x + 3

y = - x + 3

\frac{1}{s ( s + 8 )}

\int x^{x} (1 + ln (x)) d x

\frac{x ^{4} + 9}{x ^{2}}

\frac{d x}{d t} = 2 (2 x t)

\int_{- 1}^{8} 2 - 3 x d x

What is the tangent of f(x)= 1/(x-1),\at x=2 ?
The tangent of f(x)= 1/(x-1),\at x=2 is y=-x+3