What is the integral from-1 to 8 of 2-\sqrt[3]{x} ?

The integral from-1 to 8 of 2-\sqrt[3]{x} is 27/4

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integral from-1 to 8 of 2-\sqrt[3]{x}

\int_{- 1}^{8} 2 - 3 x d x

\frac{27}{4}

Decimal

6.75

Solution steps

\int_{- 1}^{8} 2 - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{8} 2 d x - \int_{- 1}^{8} 3 x d x

\int_{- 1}^{8} 2 d x = 18

\int_{- 1}^{8} 3 x d x = \frac{45}{4}

= 18 - \frac{45}{4}

Simplify

18 - \frac{45}{4} : \frac{27}{4}

= \frac{27}{4}

x \to - 1 + lim (\frac{1}{( x + 1 ) ^{2}})

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9 cos^{2} (t)

x^{3} - 1

\frac{\partial}{\partial x} (e^{y} + x + x^{2} + 5)

What is the integral from-1 to 8 of 2-\sqrt[3]{x} ?
The integral from-1 to 8 of 2-\sqrt[3]{x} is 27/4