What is the limit as x approaches-1+of 1/((x+1)^2) ?

The limit as x approaches-1+of 1/((x+1)^2) is infinity

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limit as x approaches-1+of 1/((x+1)^2)

x \to - 1 + lim (\frac{1}{( x + 1 ) ^{2}})

\infty

Solution steps

x \to - 1 + lim (\frac{1}{( x + 1 ) ^{2}})

For

x

approaching

- 1

from the right

, x > - 1 \Rightarrow (x + 1)^{2} > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\int \frac{4 x}{4 x + 1} d x

9 cos^{2} (t)

x^{3} - 1

\frac{\partial}{\partial x} (e^{y} + x + x^{2} + 5)

\frac{\partial}{\partial x} (\frac{2 y}{x ^{2} + 2})

What is the limit as x approaches-1+of 1/((x+1)^2) ?
The limit as x approaches-1+of 1/((x+1)^2) is infinity