What is the limit as x approaches 0 of (sin^2(4x))/x ?

The limit as x approaches 0 of (sin^2(4x))/x is 0

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limit as x approaches 0 of (sin^2(4x))/x

x \to 0 lim (\frac{sin ^{2} ( 4 x )}{x})

0

Solution steps

x \to 0 lim (\frac{sin ^{2} ( 4 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{4 sin ( 8 x )}{1})

= x \to 0 lim (\frac{4 sin ( 8 x )}{1})

Plug in the value

x = 0

= \frac{4 sin ( 8 \cdot 0 )}{1}

Simplify

\frac{4 sin ( 8 \cdot 0 )}{1} : 0

= 0

x \to 0 + lim (- \frac{1}{sin ( 2 x )})

4 (t + 3)

\frac{d}{d x} (y x^{y - 1})

\int \frac{2 sin ( x ) cos ( x )}{1 + tan ( x )} d x

y^{^{''}} + y^{^{'}} = 1

What is the limit as x approaches 0 of (sin^2(4x))/x ?
The limit as x approaches 0 of (sin^2(4x))/x is 0