What is the tangent of f(x)=2x^3-2x,\at x=-1 ?

The tangent of f(x)=2x^3-2x,\at x=-1 is y=4x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=2x^3-2x,\at x=-1

tangent of

f (x) = 2 x^{3} - 2 x, at x = - 1

y = 4 x + 4

Solution steps

Find the tangent point:

(- 1, 0)

Find the slope of

f (x) = 2 x^{3} - 2 x : \frac{df ( x )}{d x} = 6 x^{2} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(- 1, 0) : y = 4 x + 4

y = 4 x + 4

\frac{\partial}{\partial y} (sin (x + 2 y))

\int_{0}^{π} 2 π x sin (x) d x

\frac{\partial}{\partial x} ((x y)^{5})

\frac{d}{d x} (x^{2} \cdot I n (x))

f (x) = (1 + 2 x) (6 - 5 x), at x = 1

What is the tangent of f(x)=2x^3-2x,\at x=-1 ?
The tangent of f(x)=2x^3-2x,\at x=-1 is y=4x+4