What is the derivative of (4-x^2^3) ?

The derivative of (4-x^2^3) is -6x(4-x^2)^2

What is the first derivative of (4-x^2^3) ?

The first derivative of (4-x^2^3) is -6x(4-x^2)^2

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\frac{d}{d x} ((4 - x^{2})^{3})

- 6 x (4 - x^{2})^{2}

Solution steps

\frac{d}{d x} ((4 - x^{2})^{3})

Apply the chain rule:

3 (4 - x^{2})^{2} \frac{d}{d x} (4 - x^{2})

= 3 (4 - x^{2})^{2} \frac{d}{d x} (4 - x^{2})

\frac{d}{d x} (4 - x^{2}) = - 2 x

= 3 (4 - x^{2})^{2} (- 2 x)

Simplify

= - 6 x (4 - x^{2})^{2}

\int \frac{sin ( \frac{2}{x} )}{x ^{2}} d x

\frac{d}{d x} (\frac{5}{3} x^{2} y^{- 2})

\int \frac{2}{x ^{2} + 9} d x

n = 0 \sum \infty \frac{n}{1 + n ^{2}}

f (x) = \frac{2}{x ^{2}}, (7, \frac{2}{49})

What is the derivative of (4-x^2^3) ?
The derivative of (4-x^2^3) is -6x(4-x^2)^2
What is the first derivative of (4-x^2^3) ?
The first derivative of (4-x^2^3) is -6x(4-x^2)^2