What is the derivative of 3/(x^3) ?

The derivative of 3/(x^3) is -9/(x^4)

What is the first derivative of 3/(x^3) ?

The first derivative of 3/(x^3) is -9/(x^4)

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derivative of

\frac{3}{x ^{3}}

- \frac{9}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 3 x^{- 3 - 1})

Simplify

3 (- 3 x^{- 3 - 1}) : - \frac{9}{x ^{4}}

= - \frac{9}{x ^{4}}

\int 15 x^{4} d x

\frac{3}{s ^{2} - 4}

\frac{d}{d x} (x^{3 l n (x)})

\int - \frac{2}{3} y^{- \frac{4}{3}} d y

y = \frac{3 cos ( x )}{1 + sin ( x )}

What is the derivative of 3/(x^3) ?
The derivative of 3/(x^3) is -9/(x^4)
What is the first derivative of 3/(x^3) ?
The first derivative of 3/(x^3) is -9/(x^4)