What is (\partial)/(\partial x)((x-y)(1-xy)) ?

The answer to (\partial)/(\partial x)((x-y)(1-xy)) is 1-2xy+y^2

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(\partial)/(\partial x)((x-y)(1-xy))

\frac{\partial}{\partial x} ((x - y) (1 - x y))

1 - 2 x y + y^{2}

Solution steps

\frac{\partial}{\partial x} ((x - y) (1 - x y))

Treat

y

as a constant

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - y, g = 1 - x y

= \frac{\partial}{\partial x} (x - y) (1 - x y) + \frac{\partial}{\partial x} (1 - x y) (x - y)

\frac{\partial}{\partial x} (x - y) = 1

\frac{\partial}{\partial x} (1 - x y) = - y

= 1 \cdot (1 - x y) + (- y) (x - y)

Simplify

1 \cdot (1 - x y) + (- y) (x - y) : 1 - 2 x y + y^{2}

= 1 - 2 x y + y^{2}

\frac{d}{d x} (a x^{2} + b x^{2} + c)

\int ln (x) sin (x) d x

\int \frac{2}{x} - \frac{1}{x ^{2}} d x

\int \frac{2 x}{4 x - 5} d x

\frac{d r}{d t} = \frac{r ^{2}}{t}

What is (\partial)/(\partial x)((x-y)(1-xy)) ?
The answer to (\partial)/(\partial x)((x-y)(1-xy)) is 1-2xy+y^2