What is (d^2)/(dx^2)(cos^2(2pix)) ?

The answer to (d^2)/(dx^2)(cos^2(2pix)) is -8pi^2cos(4pix)

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(d^2)/(dx^2)(cos^2(2pix))

\frac{d ^{2}}{d x ^{2}} (cos^{2} (2 π x))

- 8 π^{2} cos (4 π x)

Solution steps

\frac{d ^{2}}{d x ^{2}} (cos^{2} (2 π x))

\frac{d}{d x} (cos^{2} (2 π x)) = - 4 π cos (2 π x) sin (2 π x)

= \frac{d}{d x} (- 4 π cos (2 π x) sin (2 π x))

\frac{d}{d x} (- 4 π cos (2 π x) sin (2 π x)) = - 8 π^{2} cos (4 π x)

= - 8 π^{2} cos (4 π x)

\int x^{3} d x

ln (x^{2} + 1)

\int_{- 2}^{0} \frac{x}{2} + 1 d x

y^{^{'}} = \frac{x e ^{y}}{y}

t^{2} y^{^{''}} - 4 t y^{^{'}} + 6 y = 0

What is (d^2)/(dx^2)(cos^2(2pix)) ?
The answer to (d^2)/(dx^2)(cos^2(2pix)) is -8pi^2cos(4pix)