en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(xe^y)/y

Solution

y^{^{'}} = \frac{x e ^{y}}{y}

Solution

y = - W (\frac{x ^{2} + c _{1}}{2 e}) - 1

Solution steps

y^{'} (x) = \frac{x e ^{y}}{y}

Solve separable ODE:

y = - W (\frac{x ^{2} + c _{1}}{2 e}) - 1

y = - W (\frac{x ^{2} + c _{1}}{2 e}) - 1

Popular Examples

t^2y^{''}-4ty^'+6y=0

t^{2} y^{^{''}} - 4 t y^{^{'}} + 6 y = 0

limit as x approaches 0 of (2x)/(2x^2)

x \to 0 lim (\frac{2 x}{2 x ^{2}})

integral from 3 to 5 of e^{6x}

\int_{3}^{5} e^{6 x} d x

derivative of f(x)=sqrt(3-2x)derivative of

f (x) = 3 - 2 x

integral of (x^4+1)/(x^2+1)

\int \frac{x ^{4} + 1}{x ^{2} + 1} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(xe^y)/y ?
The solution for y^'=(xe^y)/y is y=-\W((x^2+c_{1})/(2e))-1