What is the limit as x approaches 16 of sqrt(x+x^2) ?

The limit as x approaches 16 of sqrt(x+x^2) is 4sqrt(17)

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limit as x approaches 16 of sqrt(x+x^2)

x \to 16 lim (x + x^{2})

417

Decimal

16.49242 \dots

Solution steps

x \to 16 lim (x + x^{2})

Plug in the value

x = 16

= 16 + 1 6^{2}

Simplify

16 + 1 6^{2} : 417

= 417

4 + t^{6}

x \to - 2 lim (- x^{2} + 9 x - 4)

n = 1 \sum \infty \frac{2}{( n + 1 ) !}

x \to 0 lim (ln ((1 + \frac{1}{x})^{x}))

y^{^{''}} - 10 y^{^{'}} + 41 y = 0

What is the limit as x approaches 16 of sqrt(x+x^2) ?
The limit as x approaches 16 of sqrt(x+x^2) is 4sqrt(17)