What is the tangent of x^2+xy+2y^2=58,(5,3) ?

The tangent of x^2+xy+2y^2=58,(5,3) is y=-13/17 x+116/17

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tangent of x^2+xy+2y^2=58,(5,3)

tangent of

x^{2} + x y + 2 y^{2} = 58, (5, 3)

y = - \frac{13}{17} x + \frac{116}{17}

Solution steps

Find the slope of

x^{2} + x y + 2 y^{2} = 58 : \frac{d y}{d x} = \frac{- 2 x - y}{x + 4 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{13}{17}

Find the line with slope m=

- \frac{13}{17}

and passing through

(5, 3) : y = - \frac{13}{17} x + \frac{116}{17}

y = - \frac{13}{17} x + \frac{116}{17}

\frac{d y}{d x} = y^{2} - y

y = \frac{7}{x}

y^{^{''''}} + 4 y = 0

\frac{d}{d x} (3 e^{x} + 8 x^{2} ln^{2} (x))

f (x) = \frac{5}{x ^{11}}

What is the tangent of x^2+xy+2y^2=58,(5,3) ?
The tangent of x^2+xy+2y^2=58,(5,3) is y=-13/17 x+116/17