What is the derivative of f(x)=sqrt(3-2x) ?

The derivative of f(x)=sqrt(3-2x) is -1/(sqrt(3-2x))

What is the first derivative of f(x)=sqrt(3-2x) ?

The first derivative of f(x)=sqrt(3-2x) is -1/(sqrt(3-2x))

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derivative of

f (x) = 3 - 2 x

- \frac{1}{3 - 2 x}

Solution steps

\frac{d}{d x} (3 - 2 x)

Apply the chain rule:

\frac{1}{2 3 - 2 x} \frac{d}{d x} (3 - 2 x)

= \frac{1}{2 3 - 2 x} \frac{d}{d x} (3 - 2 x)

\frac{d}{d x} (3 - 2 x) = - 2

= \frac{1}{2 3 - 2 x} (- 2)

Simplify

\frac{1}{2 3 - 2 x} (- 2) : - \frac{1}{3 - 2 x}

= - \frac{1}{3 - 2 x}

\int \frac{x ^{4} + 1}{x ^{2} + 1} d x

0.882 a^{0.842}

\int_{- 2}^{2} ∣ x ∣ - (x^{2} - 2) d x

(x^{3} + 1) e^{x}

\int (x - 2)^{4} \frac{1}{4 x - x ^{2}} d x

What is the derivative of f(x)=sqrt(3-2x) ?
The derivative of f(x)=sqrt(3-2x) is -1/(sqrt(3-2x))
What is the first derivative of f(x)=sqrt(3-2x) ?
The first derivative of f(x)=sqrt(3-2x) is -1/(sqrt(3-2x))