What is the integral of 9/32+9/8 x^2 ?

The integral of 9/32+9/8 x^2 is 9/32 x+(3x^3)/8+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 9/32+9/8 x^2

\int \frac{9}{32} + \frac{9}{8} x^{2} d x

\frac{9}{32} x + \frac{3 x ^{3}}{8} + C

Solution steps

\int \frac{9}{32} + \frac{9}{8} x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{9}{32} d x + \int \frac{9}{8} x^{2} d x

\int \frac{9}{32} d x = \frac{9}{32} x

\int \frac{9}{8} x^{2} d x = \frac{3 x ^{3}}{8}

= \frac{9}{32} x + \frac{3 x ^{3}}{8}

Add a constant to the solution

= \frac{9}{32} x + \frac{3 x ^{3}}{8} + C

\int \frac{6}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

\frac{\partial}{\partial v} (2 u)

\frac{\partial}{\partial x} (20 - 5 x y - 5 x)

x \to 2 + lim (x - 3)

\int_{1}^{2} \frac{2}{x ^{2}} d x

What is the integral of 9/32+9/8 x^2 ?
The integral of 9/32+9/8 x^2 is 9/32 x+(3x^3)/8+C