What is the limit as x approaches 0 of (8e^{2x}-8e^{-4x}-36x-6)/(3x^2+4x) ?

The limit as x approaches 0 of (8e^{2x}-8e^{-4x}-36x-6)/(3x^2+4x) is diverges

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limit as x approaches 0 of (8e^{2x}-8e^{-4x}-36x-6)/(3x^2+4x)

x \to 0 lim (\frac{8 e ^{2 x} - 8 e ^{- 4 x} - 36 x - 6}{3 x ^{2} + 4 x})

diverges

Solution steps

x \to 0 lim (\frac{8 e ^{2 x} - 8 e ^{- 4 x} - 36 x - 6}{3 x ^{2} + 4 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{8 e ^{2 x} - 8 e ^{- 4 x} - 36 x - 6}{3 x ^{2} + 4 x}) = - \infty

x \to 0 - lim (\frac{8 e ^{2 x} - 8 e ^{- 4 x} - 36 x - 6}{3 x ^{2} + 4 x}) = \infty

= diverges

\int - x^{n} d x

x^{2} - 8 x - 5

\int \frac{x + 3}{x ^{2} + 16} d x

t \to 8 lim (\frac{t ( t - 5 ) - 24}{t ^{2} - 8 t})

z \to 2 i lim (\frac{1 - z}{1 + z})

What is the limit as x approaches 0 of (8e^{2x}-8e^{-4x}-36x-6)/(3x^2+4x) ?
The limit as x approaches 0 of (8e^{2x}-8e^{-4x}-36x-6)/(3x^2+4x) is diverges