What is the limit as t approaches 8 of (t(t-5)-24)/(t^2-8t) ?

The limit as t approaches 8 of (t(t-5)-24)/(t^2-8t) is 11/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches 8 of (t(t-5)-24)/(t^2-8t)

t \to 8 lim (\frac{t ( t - 5 ) - 24}{t ^{2} - 8 t})

\frac{11}{8}

Decimal

1.375

Solution steps

t \to 8 lim (\frac{t ( t - 5 ) - 24}{t ^{2} - 8 t})

Simplify

\frac{t ( t - 5 ) - 24}{t ^{2} - 8 t} : \frac{t + 3}{t}

= t \to 8 lim (\frac{t + 3}{t})

Plug in the value

t = 8

= \frac{8 + 3}{8}

Simplify

= \frac{11}{8}

z \to 2 i lim (\frac{1 - z}{1 + z})

n = 1 \sum \infty 3 r^{n}

x \to 3 - lim (2 x + 5)

x \to \infty lim (4 x + 14)

\frac{d}{d x} (ln (x) + c)

What is the limit as t approaches 8 of (t(t-5)-24)/(t^2-8t) ?
The limit as t approaches 8 of (t(t-5)-24)/(t^2-8t) is 11/8