What is the sum from n=1 to infinity of 3r^n ?

The sum from n=1 to infinity of 3r^n is Radius of convergence is 1, Interval of convergence is-1<r<1

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sum from n=1 to infinity of 3r^n

n = 1 \sum \infty 3 r^{n}

Radius of convergence is 1, Interval of convergence is - 1 < r < 1

Solution steps

n = 1 \sum \infty 3 r^{n}

Use the Ratio Test to compute the convergence interval

Radius of convergence is 1, Interval of convergence is - 1 < r < 1

x \to 3 - lim (2 x + 5)

x \to \infty lim (4 x + 14)

\frac{d}{d x} (ln (x) + c)

\frac{\partial}{\partial x} (54 - \frac{2}{3} x^{2} - 4 y^{2})

\int \frac{3}{1 - x ^{2}} d x

What is the sum from n=1 to infinity of 3r^n ?
The sum from n=1 to infinity of 3r^n is Radius of convergence is 1, Interval of convergence is-1<r<1