What is the derivative of ln(x+c) ?

The derivative of ln(x+c) is 1/x

What is the first derivative of ln(x+c) ?

The first derivative of ln(x+c) is 1/x

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\frac{d}{d x} (ln (x) + c)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (x) + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (x)) + \frac{d c}{d x}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d c}{d x} = 0

= \frac{1}{x} + 0

Simplify

= \frac{1}{x}

\frac{\partial}{\partial x} (54 - \frac{2}{3} x^{2} - 4 y^{2})

\int \frac{3}{1 - x ^{2}} d x

\int_{0}^{l n (3)} \frac{4}{e ^{x} + 2} d x

t \to 0 lim (\frac{4}{t} - \frac{4}{e ^{t} - 1})

x \to 4 lim (2 x - 1)

What is the derivative of ln(x+c) ?
The derivative of ln(x+c) is 1/x
What is the first derivative of ln(x+c) ?
The first derivative of ln(x+c) is 1/x