What is the tangent of f(x)=(x-9)/(8x-1),\at x=1 ?

The tangent of f(x)=(x-9)/(8x-1),\at x=1 is y= 71/49 x-127/49

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tangent of f(x)=(x-9)/(8x-1),\at x=1

tangent of

f (x) = \frac{x - 9}{8 x - 1}, at x = 1

y = \frac{71}{49} x - \frac{127}{49}

Solution steps

Find the tangent point:

(1, - \frac{8}{7})

Find the slope of

f (x) = \frac{x - 9}{8 x - 1} : \frac{df ( x )}{d x} = \frac{71}{( 8 x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{71}{49}

Find the line with slope m=

\frac{71}{49}

and passing through

(1, - \frac{8}{7}) : y = \frac{71}{49} x - \frac{127}{49}

y = \frac{71}{49} x - \frac{127}{49}

lo g_{3} (x)

y^{^{'''}} + 6 y^{^{''}} - 15 y^{^{'}} + 8 y = 0

\frac{d}{d x} (\frac{x ^{2}}{9 + 4 x})

\int_{\frac{1}{7}}^{5} 8 x ln (7 x) d x

f^{^{'}} (x) = x (x - 3)

What is the tangent of f(x)=(x-9)/(8x-1),\at x=1 ?
The tangent of f(x)=(x-9)/(8x-1),\at x=1 is y= 71/49 x-127/49