What is the integral from 1/7 to 5 of 8xln(7x) ?

The integral from 1/7 to 5 of 8xln(7x) is 8(-306/49+25/2 ln(35))

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integral from 1/7 to 5 of 8xln(7x)

\int_{\frac{1}{7}}^{5} 8 x ln (7 x) d x

8 (- \frac{306}{49} + \frac{25}{2} ln (35))

Decimal

305.57562 \dots

Solution steps

\int_{\frac{1}{7}}^{5} 8 x ln (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{\frac{1}{7}}^{5} x ln (7 x) d x

Apply Integration By Parts

: [\frac{1}{2} x^{2} ln (7 x) - \int \frac{x}{2} d x]_{\frac{1}{7}}^{5}

= 8 [\frac{1}{2} x^{2} ln (7 x) - \int \frac{x}{2} d x]_{\frac{1}{7}}^{5}

\int \frac{x}{2} d x = \frac{x ^{2}}{4}

= 8 [\frac{1}{2} x^{2} ln (7 x) - \frac{x ^{2}}{4}]_{\frac{1}{7}}^{5}

Compute the boundaries:

- \frac{306}{49} + \frac{25}{2} ln (35)

= 8 (- \frac{306}{49} + \frac{25}{2} ln (35))

f^{^{'}} (x) = x (x - 3)

3 x y^{2}

\frac{\partial}{\partial z} (ln (x^{2} + y^{2} + z^{2}))

\frac{\partial}{\partial y} (e^{y} cos (x))

x \to 0 lim (e^{x + 1})

What is the integral from 1/7 to 5 of 8xln(7x) ?
The integral from 1/7 to 5 of 8xln(7x) is 8(-306/49+25/2 ln(35))