What is the integral of 4/(x(ln(x))^3) ?

The integral of 4/(x(ln(x))^3) is -2/(ln^2(x))+C

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integral of 4/(x(ln(x))^3)

\int \frac{4}{x ( ln ( x ) ) ^{3}} d x

- \frac{2}{ln ^{2} ( x )} + C

Solution steps

\int \frac{4}{x ( ln ( x ) ) ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{x ( ln ( x ) ) ^{3}} d x

Apply u-substitution

: \int \frac{1}{u ^{3}} d u

= 4 \cdot \int \frac{1}{u ^{3}} d u

Apply the Power Rule

: - \frac{1}{2 u ^{2}}

= 4 (- \frac{1}{2 u ^{2}})

Substitute back

u = ln (x)

= 4 (- \frac{1}{2 ln ^{2} ( x )})

Simplify

4 (- \frac{1}{2 ln ^{2} ( x )}) : - \frac{2}{ln ^{2} ( x )}

= - \frac{2}{ln ^{2} ( x )}

Add a constant to the solution

= - \frac{2}{ln ^{2} ( x )} + C

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What is the integral of 4/(x(ln(x))^3) ?
The integral of 4/(x(ln(x))^3) is -2/(ln^2(x))+C