What is implicit 6x^2+3y^2=12 ?

The answer to implicit 6x^2+3y^2=12 is (dy}{dx}=-\frac{2x)/y

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implicit 6x^2+3y^2=12

implicit derivative

6 x^{2} + 3 y^{2} = 12

\frac{d y}{d x} = - \frac{2 x}{y}

Solution steps

6 x^{2} + 3 y^{2} = 12

Treat

y

y (x)

Differentiate both sides:

12 x + 6 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{2 x}{y}

\frac{d y}{d x} = - \frac{2 x}{y}

\int (x^{3} - \frac{1}{x ^{3}}) (x^{3} + \frac{1}{x ^{3}}) d x

\frac{d}{d u} (u^{2} v)

\int sin (\frac{x}{2}) cos (\frac{2 x}{3}) d x

81 m^{8} + 2 m^{4} + 1

arcsin (4 x + 1)

What is implicit 6x^2+3y^2=12 ?
The answer to implicit 6x^2+3y^2=12 is (dy}{dx}=-\frac{2x)/y