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Popular >

y^'+2y= 6/5

Solution

y^{^{'}} + 2 y = \frac{6}{5}

Solution

y = - \frac{e ^{- 2 t - c_{1}}}{10} + \frac{3}{5}

Solution steps

y^{'} (t) + 2 y = \frac{6}{5}

Solve separable ODE:

y = - \frac{e ^{- 2 t - c_{1}}}{10} + \frac{3}{5}

y = - \frac{e ^{- 2 t - c_{1}}}{10} + \frac{3}{5}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y= 6/5 ?
The solution for y^'+2y= 6/5 is y=-(e^{-2t-c_{1}})/(10)+3/5