What is the tangent of f(x)=-5-3x^2,-53,\at x=4 ?

The tangent of f(x)=-5-3x^2,-53,\at x=4 is y=-24x+43

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tangent of f(x)=-5-3x^2,-53,\at x=4

tangent of

f (x) = - 5 - 3 x^{2}, - 53, at x = 4

y = - 24 x + 43

Solution steps

Find the tangent point:

(4, - 53)

Find the slope of

f (x) = - 5 - 3 x^{2} : \frac{df ( x )}{d x} = - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 24

Find the line with slope m=

- 24

and passing through

(4, - 53) : y = - 24 x + 43

y = - 24 x + 43

(- 3.2) (7.6)

\int x^{2} (x^{3} - 1)^{10} d x

x \to - 3 lim (\frac{7}{x ^{7}})

\int x 2 d x

z \to 0 lim (\frac{1}{1 + \frac{1}{z}})

What is the tangent of f(x)=-5-3x^2,-53,\at x=4 ?
The tangent of f(x)=-5-3x^2,-53,\at x=4 is y=-24x+43