What is the derivative of x^2-4x+7 ?

The derivative of x^2-4x+7 is 2x-4

What is the first derivative of x^2-4x+7 ?

The first derivative of x^2-4x+7 is 2x-4

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\frac{d}{d x} (x^{2} - 4 x + 7)

2 x - 4

Solution steps

\frac{d}{d x} (x^{2} - 4 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (7) = 0

= 2 x - 4 + 0

Simplify

= 2 x - 4

\int \frac{x ^{2} + 2 x + 8}{x ^{4} - 4 x ^{2}} d x

\int_{1}^{2} \frac{- 1 ln ( x )}{x ^{2}} d x

\frac{\partial}{\partial x} (2 x^{2} + y^{2})

n \to \infty lim (1.0 4^{n})

\frac{d}{d x} (- x^{3} + 6 x^{2} - 9 x)

What is the derivative of x^2-4x+7 ?
The derivative of x^2-4x+7 is 2x-4
What is the first derivative of x^2-4x+7 ?
The first derivative of x^2-4x+7 is 2x-4