What is the derivative of-x^2+6x ?

The derivative of-x^2+6x is -2x+6

What is the first derivative of-x^2+6x ?

The first derivative of-x^2+6x is -2x+6

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\frac{d}{d x} (- x^{2} + 6 x)

- 2 x + 6

Solution steps

\frac{d}{d x} (- x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

= - 2 x + 6

f (x) = - 5 x^{2}, at x = 6

\frac{\partial}{\partial x} (x - y)

\frac{d}{d x} (2 x e^{6 x} + e^{6 x} \cdot 6 x^{2})

\int 2 x^{2} sin (x) d x

\frac{d}{d x} ((x^{2} + x^{3})^{4})

What is the derivative of-x^2+6x ?
The derivative of-x^2+6x is -2x+6
What is the first derivative of-x^2+6x ?
The first derivative of-x^2+6x is -2x+6