What is the integral of 6^{-x} ?

The integral of 6^{-x} is -(6^{-x})/(ln(6))+C

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integral of 6^{-x}

\int 6^{- x} d x

- \frac{6 ^{- x}}{ln ( 6 )} + C

Solution steps

\int 6^{- x} d x

Apply u-substitution

: \int - 6^{u} d u

= \int - 6^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int 6^{u} d u

\int a^{x} d x = \frac{a ^{x}}{ln a}

= - \frac{6 ^{u}}{ln ( 6 )}

Substitute back

u = - x

= - \frac{6 ^{- x}}{ln ( 6 )}

Add a constant to the solution

= - \frac{6 ^{- x}}{ln ( 6 )} + C

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