What is the tangent of y=(2x)/(x+1),\at x=1 ?

The tangent of y=(2x)/(x+1),\at x=1 is y= 1/2 x+1/2

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tangent of y=(2x)/(x+1),\at x=1

tangent of

y = \frac{2 x}{x + 1}, at x = 1

y = \frac{1}{2} x + \frac{1}{2}

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

y = \frac{2 x}{x + 1} : \frac{d y}{d x} = \frac{2}{( x + 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(1, 1) : y = \frac{1}{2} x + \frac{1}{2}

y = \frac{1}{2} x + \frac{1}{2}

2 \frac{d y}{d x} + 4 y = 1

f (x) = cos (x^{4})

y = t

x \to 0 lim (sin^{5} (2 x^{2}))

\frac{d}{d x} (x^{3} - 3 x + 6)

What is the tangent of y=(2x)/(x+1),\at x=1 ?
The tangent of y=(2x)/(x+1),\at x=1 is y= 1/2 x+1/2