What is the derivative of x^3-3x+6 ?

The derivative of x^3-3x+6 is 3x^2-3

What is the first derivative of x^3-3x+6 ?

The first derivative of x^3-3x+6 is 3x^2-3

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\frac{d}{d x} (x^{3} - 3 x + 6)

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (6) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

\frac{d}{d x} (e^{- 2 x + 1})

g (t) = \frac{3}{t}

f (x) = \frac{3}{x - 1}

y^{^{''}} + (\frac{2}{x}) y^{^{'}} = 2 x + 4

(x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0, y (1) = 0

What is the derivative of x^3-3x+6 ?
The derivative of x^3-3x+6 is 3x^2-3
What is the first derivative of x^3-3x+6 ?
The first derivative of x^3-3x+6 is 3x^2-3