What is the derivative of x^2-2x+1 ?

The derivative of x^2-2x+1 is 2x-2

What is the first derivative of x^2-2x+1 ?

The first derivative of x^2-2x+1 is 2x-2

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derivative of

x^{2} - 2 x + 1

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x - 2 + 0

Simplify

= 2 x - 2

2 x y + 6 x + (x^{2} - 4) y^{^{'}} = 0

y = (9 x + 5) x^{2}

n = 1 \sum \infty \frac{1 ^{n}}{n + 2}

x \to 2 - lim (c x^{2} + 6 x)

\int \frac{x ^{2} + 32 x - 16}{x ^{3} - 16 x} d x

What is the derivative of x^2-2x+1 ?
The derivative of x^2-2x+1 is 2x-2
What is the first derivative of x^2-2x+1 ?
The first derivative of x^2-2x+1 is 2x-2