What is the derivative of 2x^2-x+1 ?

The derivative of 2x^2-x+1 is 4x-1

What is the first derivative of 2x^2-x+1 ?

The first derivative of 2x^2-x+1 is 4x-1

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\frac{d}{d x} (2 x^{2} - x + 1)

4 x - 1

Solution steps

\frac{d}{d x} (2 x^{2} - x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 4 x - 1 + 0

Simplify

= 4 x - 1

f (x) = x^{2} - x + 7, at x = 2

x y - 5 y^{2} = 4 (12.2)

\int_{- 3}^{4} \frac{8}{x ^{3}} d x

\frac{d y}{d x} + \frac{1}{x} y = 5 x^{2}

\frac{d}{d x} (\frac{a + b x}{a - b x})

What is the derivative of 2x^2-x+1 ?
The derivative of 2x^2-x+1 is 4x-1
What is the first derivative of 2x^2-x+1 ?
The first derivative of 2x^2-x+1 is 4x-1