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Popular >

integral from 1 to 2 of (6x-1)

Solution

\int_{1}^{2} (6 x - 1) d x

Solution

8

Solution steps

\int_{1}^{2} 6 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 6 x d x - \int_{1}^{2} 1 d x

\int_{1}^{2} 6 x d x = 9

\int_{1}^{2} 1 d x = 1

= 9 - 1

Simplify

= 8

Popular Examples

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\int sin^{5} (4 x) cos^{3} (4 x) d x

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(d^2)/(dx^2)(e^{cos(x)})

\frac{d ^{2}}{d x ^{2}} (e^{c o s (x)})

integral of-1/(1+9x^2)

\int - \frac{1}{1 + 9 x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (6x-1) ?
The integral from 1 to 2 of (6x-1) is 8