What is the solution for y^'=y(y^3-1) ?

The solution for y^'=y(y^3-1) is y=\sqrt[3]{1/(1-e^{3(t+c_{1))}}}

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y^'=y(y^3-1)

y^{^{'}} = y (y^{3} - 1)

Solution steps

y^{'} (t) = y (y^{3} - 1)

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What is the solution for y^'=y(y^3-1) ?
The solution for y^'=y(y^3-1) is y=\sqrt[3]{1/(1-e^{3(t+c_{1))}}}