What is laplacetransform 4-2e^{-4t} ?

The answer to laplacetransform 4-2e^{-4t} is 4/s-2/(s+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 4-2e^{-4t}

laplace transform

4 - 2 e^{- 4 t}

\frac{4}{s} - \frac{2}{s + 4}

Solution steps

L {4 - 2 e^{- 4 t}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {4} - 2 L {e^{- 4 t}}

L {4} : \frac{4}{s}

L {e^{- 4 t}} : \frac{1}{s + 4}

= \frac{4}{s} - 2 \cdot \frac{1}{s + 4}

Refine

\frac{4}{s} - 2 \frac{1}{s + 4} : \frac{4}{s} - \frac{2}{s + 4}

= \frac{4}{s} - \frac{2}{s + 4}

(\frac{ln ( x )}{x})^{^{'}}

x \to + 4 lim (x - 2)

\int_{0}^{π} (x cos (2 x)) d x

\frac{d y}{d t} - 0.1 y = - t

\frac{d}{d x} (\frac{9 - x ^{2}}{( 9 + x ^{2} ) ^{2}})

What is laplacetransform 4-2e^{-4t} ?
The answer to laplacetransform 4-2e^{-4t} is 4/s-2/(s+4)