What is the derivative of 5/((x^2-3x^2)) ?

The derivative of 5/((x^2-3x^2)) is -(10(2x-3))/((x^2-3x)^3)

What is the first derivative of 5/((x^2-3x^2)) ?

The first derivative of 5/((x^2-3x^2)) is -(10(2x-3))/((x^2-3x)^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{5}{( x ^{2} - 3 x ) ^{2}})

- \frac{10 ( 2 x - 3 )}{( x ^{2} - 3 x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{5}{( x ^{2} - 3 x ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{( x ^{2} - 3 x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((x^{2} - 3 x)^{- 2})

Apply the chain rule:

- \frac{2}{( x ^{2} - 3 x ) ^{3}} \frac{d}{d x} (x^{2} - 3 x)

= - \frac{2}{( x ^{2} - 3 x ) ^{3}} \frac{d}{d x} (x^{2} - 3 x)

\frac{d}{d x} (x^{2} - 3 x) = 2 x - 3

= 5 (- \frac{2}{( x ^{2} - 3 x ) ^{3}} (2 x - 3))

Simplify

5 (- \frac{2}{( x ^{2} - 3 x ) ^{3}} (2 x - 3)) : - \frac{10 ( 2 x - 3 )}{( x ^{2} - 3 x ) ^{3}}

= - \frac{10 ( 2 x - 3 )}{( x ^{2} - 3 x ) ^{3}}

16 t^{2}

\frac{( 3 x )}{2}, 3, 2 - (\frac{1}{2} x)

\frac{d}{d x} (\frac{1 - 3 x}{5 + x})

\int t^{6} (3 + t^{7})^{6} d t

\frac{\partial}{\partial x} (- e^{c o s (x)} sin (x))

What is the derivative of 5/((x^2-3x^2)) ?
The derivative of 5/((x^2-3x^2)) is -(10(2x-3))/((x^2-3x)^3)
What is the first derivative of 5/((x^2-3x^2)) ?
The first derivative of 5/((x^2-3x^2)) is -(10(2x-3))/((x^2-3x)^3)