What is the tangent of f(x)= x/(x+3),\at x=-5 ?

The tangent of f(x)= x/(x+3),\at x=-5 is y= 3/4 x+25/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)= x/(x+3),\at x=-5

tangent of

f (x) = \frac{x}{x + 3}, at x = - 5

y = \frac{3}{4} x + \frac{25}{4}

Solution steps

Find the tangent point:

(- 5, \frac{5}{2})

Find the slope of

f (x) = \frac{x}{x + 3} : \frac{df ( x )}{d x} = \frac{3}{( x + 3 ) ^{2}}

Compute the slope of

f (x) = \frac{x}{x + 3}

x = - 5 : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(- 5, \frac{5}{2}) : y = \frac{3}{4} x + \frac{25}{4}

y = \frac{3}{4} x + \frac{25}{4}

9 x^{2} \cdot cos (x) \cdot cot (x)

\frac{\partial}{\partial x} (r (θ, x) sin (θ))

x = 5, y = 5 x

\frac{sin ( 5 x )}{3 x}

\frac{\partial}{\partial x} (y^{2} - x^{2} - x^{3})

What is the tangent of f(x)= x/(x+3),\at x=-5 ?
The tangent of f(x)= x/(x+3),\at x=-5 is y= 3/4 x+25/4