What is the integral from 0 to 2 of xsqrt(11-x^2) ?

The integral from 0 to 2 of xsqrt(11-x^2) is (11sqrt(11)-7sqrt(7))/3

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integral from 0 to 2 of xsqrt(11-x^2)

\int_{0}^{2} x 11 - x^{2} d x

\frac{11 11 - 7 7}{3}

Decimal

5.98753 \dots

Solution steps

\int_{0}^{2} x 11 - x^{2} d x

Apply u-substitution

: \int_{11}^{7} - \frac{u}{2} d u

= \int_{11}^{7} - \frac{u}{2} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{7}^{11} - \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \frac{1}{2} \cdot \int_{7}^{11} u d u)

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{7}^{11}

= - (- \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{7}^{11})

Simplify

= \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{7}^{11}

Compute the boundaries:

\frac{22 11 - 14 7}{3}

= \frac{1}{2} \cdot \frac{22 11 - 14 7}{3}

Simplify

= \frac{11 11 - 7 7}{3}

\int (x^{2} + 5) e^{- x} d x

\int \frac{( x ^{5} + 2 x ^{2} - 1 )}{x ^{4}} d x

2 y^{^{'}} + y = \frac{3}{2} t^{2}

x \to - 2 lim (\frac{2 x}{x + 2})

\frac{d}{d t} (cos (4 t))

What is the integral from 0 to 2 of xsqrt(11-x^2) ?
The integral from 0 to 2 of xsqrt(11-x^2) is (11sqrt(11)-7sqrt(7))/3