What is the integral from-6 to-2 of (-x^2-8x-18) ?

The integral from-6 to-2 of (-x^2-8x-18) is -40/3

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integral from-6 to-2 of (-x^2-8x-18)

\int_{- 6}^{- 2} (- x^{2} - 8 x - 18) d x

- \frac{40}{3}

Decimal

- 13.33333 \dots

Solution steps

\int_{- 6}^{- 2} - x^{2} - 8 x - 18 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 6}^{- 2} x^{2} d x - \int_{- 6}^{- 2} 8 x d x - \int_{- 6}^{- 2} 18 d x

\int_{- 6}^{- 2} x^{2} d x = \frac{208}{3}

\int_{- 6}^{- 2} 8 x d x = - 128

\int_{- 6}^{- 2} 18 d x = 72

= - \frac{208}{3} - (- 128) - 72

Simplify

- \frac{208}{3} - (- 128) - 72 : - \frac{40}{3}

= - \frac{40}{3}

(\frac{x}{( x + 1 ) ^{2}})^{^{'}}

\frac{\partial}{\partial z} (x^{2} sin (z))

x \to 0 lim (5 x cot (2 x))

\int \frac{1}{s ^{2} + 6 s + 11} d s

y = x^{2} + x + 8

What is the integral from-6 to-2 of (-x^2-8x-18) ?
The integral from-6 to-2 of (-x^2-8x-18) is -40/3