What is the derivative of g(t)=2t^{(-3)/4} ?

The derivative of g(t)=2t^{(-3)/4} is -3/(2t^{7/4)}

What is the first derivative of g(t)=2t^{(-3)/4} ?

The first derivative of g(t)=2t^{(-3)/4} is -3/(2t^{7/4)}

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derivative of

g (t) = 2 t^{\frac{- 3}{4}}

- \frac{3}{2 t ^{\frac{7}{4}}}

Solution steps

\frac{d}{d t} (2 t^{\frac{- 3}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t^{\frac{- 3}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot \frac{- 3}{4} t^{\frac{- 3}{4} - 1}

Simplify

2 \cdot \frac{- 3}{4} t^{\frac{- 3}{4} - 1} : - \frac{3}{2 t ^{\frac{7}{4}}}

= - \frac{3}{2 t ^{\frac{7}{4}}}

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What is the derivative of g(t)=2t^{(-3)/4} ?
The derivative of g(t)=2t^{(-3)/4} is -3/(2t^{7/4)}
What is the first derivative of g(t)=2t^{(-3)/4} ?
The first derivative of g(t)=2t^{(-3)/4} is -3/(2t^{7/4)}