What is the derivative of y=-3/(4x^4)+(24)/(5x^5) ?

The derivative of y=-3/(4x^4)+(24)/(5x^5) is 3/(x^5)-(24)/(x^6)

What is the first derivative of y=-3/(4x^4)+(24)/(5x^5) ?

The first derivative of y=-3/(4x^4)+(24)/(5x^5) is 3/(x^5)-(24)/(x^6)

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derivative of

y = - \frac{3}{4 x ^{4}} + \frac{24}{5 x ^{5}}

\frac{3}{x ^{5}} - \frac{24}{x ^{6}}

Solution steps

\frac{d}{d x} (- \frac{3}{4 x ^{4}} + \frac{24}{5 x ^{5}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (\frac{3}{4 x ^{4}}) + \frac{d}{d x} (\frac{24}{5 x ^{5}})

\frac{d}{d x} (\frac{3}{4 x ^{4}}) = - \frac{3}{x ^{5}}

\frac{d}{d x} (\frac{24}{5 x ^{5}}) = - \frac{24}{x ^{6}}

= - (- \frac{3}{x ^{5}}) - \frac{24}{x ^{6}}

Simplify

= \frac{3}{x ^{5}} - \frac{24}{x ^{6}}

(x + 1) - 1

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\int x^{2} x^{2} - a^{2} d x

\int_{- \infty}^{- 1} e^{- 8 t} d t

What is the derivative of y=-3/(4x^4)+(24)/(5x^5) ?
The derivative of y=-3/(4x^4)+(24)/(5x^5) is 3/(x^5)-(24)/(x^6)
What is the first derivative of y=-3/(4x^4)+(24)/(5x^5) ?
The first derivative of y=-3/(4x^4)+(24)/(5x^5) is 3/(x^5)-(24)/(x^6)