What is the derivative of 1+3sin^2(x) ?

The derivative of 1+3sin^2(x) is 3sin(2x)

What is the first derivative of 1+3sin^2(x) ?

The first derivative of 1+3sin^2(x) is 3sin(2x)

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\frac{d}{d x} (1 + 3 sin^{2} (x))

3 sin (2 x)

Solution steps

\frac{d}{d x} (1 + 3 sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3 sin^{2} (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 sin^{2} (x)) = 3 sin (2 x)

= 0 + 3 sin (2 x)

Simplify

= 3 sin (2 x)

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y = x^{2} - 3 x, x = 0, x = 7, y = 4 x

\frac{\partial}{\partial y} (x y + yz + x z)

What is the derivative of 1+3sin^2(x) ?
The derivative of 1+3sin^2(x) is 3sin(2x)
What is the first derivative of 1+3sin^2(x) ?
The first derivative of 1+3sin^2(x) is 3sin(2x)