What is (\partial)/(\partial x)(e^{-2x^2-3y^2}) ?

The answer to (\partial)/(\partial x)(e^{-2x^2-3y^2}) is -4e^{-2x^2-3y^2}x

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(\partial)/(\partial x)(e^{-2x^2-3y^2})

\frac{\partial}{\partial x} (e^{- 2 x^{2} - 3 y^{2}})

- 4 e^{- 2 x^{2} - 3 y^{2}} x

Solution steps

\frac{\partial}{\partial x} (e^{- 2 x^{2} - 3 y^{2}})

Treat

y

as a constant

Apply the chain rule:

e^{- 2 x^{2} - 3 y^{2}} \frac{\partial}{\partial x} (- 2 x^{2} - 3 y^{2})

= e^{- 2 x^{2} - 3 y^{2}} \frac{\partial}{\partial x} (- 2 x^{2} - 3 y^{2})

\frac{\partial}{\partial x} (- 2 x^{2} - 3 y^{2}) = - 4 x

= e^{- 2 x^{2} - 3 y^{2}} (- 4 x)

Simplify

= - 4 e^{- 2 x^{2} - 3 y^{2}} x

\int 9 x^{3} (x^{3} + 2 x^{2} + x + 8) d x

x \to 4 - lim (c x^{2} + 7 x)

\int \frac{1}{2} (x - \frac{1}{2} sin (2 x)) d x

f (x) = \frac{2}{3 x ^{2}}

What is (\partial)/(\partial x)(e^{-2x^2-3y^2}) ?
The answer to (\partial)/(\partial x)(e^{-2x^2-3y^2}) is -4e^{-2x^2-3y^2}x