What is the tangent of f(x)=e^x,\at x=ln(14) ?

The tangent of f(x)=e^x,\at x=ln(14) is y=14x+14-14ln(14)

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tangent of f(x)=e^x,\at x=ln(14)

tangent of

f (x) = e^{x}, at x = ln (14)

y = 14 x + 14 - 14 ln (14)

Solution steps

Find the tangent point:

(ln (14), 14)

Find the slope of

f (x) = e^{x} : \frac{df ( x )}{d x} = e^{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 14

Find the line with slope m=

14

and passing through

(ln (14), 14) : y = 14 x + 14 - 14 ln (14)

y = 14 x + 14 - 14 ln (14)

x \to 2 lim (2 x - 4 + 8)

\int (cot (x)) d x

\frac{d}{d x} (\frac{8}{3 x ^{2}} + \frac{3}{2 x} + 2)

3 x + 7

f^{^{'}} (x) = x^{4} (x - 2) (x + 3)

What is the tangent of f(x)=e^x,\at x=ln(14) ?
The tangent of f(x)=e^x,\at x=ln(14) is y=14x+14-14ln(14)