What is the solution for (-1xy^2+2y)dx+(-1x^2y+2x)dy=0 ?

The solution for (-1xy^2+2y)dx+(-1x^2y+2x)dy=0 is y=(c_{1})/x

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(-1xy^2+2y)dx+(-1x^2y+2x)dy=0

(- 1 x y^{2} + 2 y) d x + (- 1 x^{2} y + 2 x) d y = 0

y = \frac{c _{1}}{x}

Solution steps

(- 1 x y^{2} + 2 y) d x + (- 1 x^{2} y + 2 x) d y = 0

Solve linear ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

4 sec (θ)

\frac{\partial}{\partial x} (x^{\frac{3}{2}} y)

\frac{d}{d x} ((5 x + 6)^{2})

f (x) = 4 x, at x = 9

5 \frac{d y}{d x} + 2 x = 3

What is the solution for (-1xy^2+2y)dx+(-1x^2y+2x)dy=0 ?
The solution for (-1xy^2+2y)dx+(-1x^2y+2x)dy=0 is y=(c_{1})/x