What is the derivative of f(t)=(4t^2+5) ?

The derivative of f(t)=(4t^2+5) is 8t

What is the first derivative of f(t)=(4t^2+5) ?

The first derivative of f(t)=(4t^2+5) is 8t

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derivative of

f (t) = (4 t^{2} + 5)

8 t

Solution steps

\frac{d}{d t} ((4 t^{2} + 5))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4 t^{2}) + \frac{d}{d t} (5)

\frac{d}{d t} (4 t^{2}) = 8 t

\frac{d}{d t} (5) = 0

= 8 t + 0

Simplify

= 8 t

f (x) = 4 t - 4 e^{t}

\int sin (21 x) d x

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What is the derivative of f(t)=(4t^2+5) ?
The derivative of f(t)=(4t^2+5) is 8t
What is the first derivative of f(t)=(4t^2+5) ?
The first derivative of f(t)=(4t^2+5) is 8t