What is the derivative of 2sqrt(x+8) ?

The derivative of 2sqrt(x+8) is 1/(sqrt(x+8))

What is the first derivative of 2sqrt(x+8) ?

The first derivative of 2sqrt(x+8) is 1/(sqrt(x+8))

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\frac{d}{d x} (2 x + 8)

\frac{1}{x + 8}

Solution steps

\frac{d}{d x} (2 x + 8)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x + 8)

Apply the chain rule:

\frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

= \frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= 2 \cdot \frac{1}{2 x + 8} \cdot 1

Simplify

2 \cdot \frac{1}{2 x + 8} \cdot 1 : \frac{1}{x + 8}

= \frac{1}{x + 8}

e^{4 x} \cdot 4

π^{x}

n = 0 \sum \infty 2 + 4 + 6 + 8

\int \frac{4 x ^{2} + x + 37}{( x + 1 ) ( x ^{2} + 9 )} d x

\frac{d}{d x} ((x^{2} + 7)^{3})

What is the derivative of 2sqrt(x+8) ?
The derivative of 2sqrt(x+8) is 1/(sqrt(x+8))
What is the first derivative of 2sqrt(x+8) ?
The first derivative of 2sqrt(x+8) is 1/(sqrt(x+8))