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Popular >

y-x+xy^'=0

Solution

y - x + x y^{^{'}} = 0

Solution

y = \frac{x}{2} + \frac{c _{1}}{x}

Solution steps

y - x + x y^{'} (x) = 0

Solve linear ODE:

y = \frac{x}{2} + \frac{c _{1}}{x}

y = \frac{x}{2} + \frac{c _{1}}{x}

Graph

Popular Examples

integral from 3 to x^3 of t^4

\int_{3}^{x^{3}} t^{4} d t

integral from 0 to 2 of sqrt(2x-x^2)

\int_{0}^{2} 2 x - x^{2} d x

(\partial}{\partial y}(\frac{(2x+y))/z)

\frac{\partial}{\partial y} (\frac{( 2 x + y )}{z})

tangent of f(x)= 4/(sqrt(x)),(4,2)tangent of

f (x) = \frac{4}{x}, (4, 2)

derivative of 4e^{4x}derivative of

4 e^{4 x}

Frequently Asked Questions (FAQ)

What is the solution for y-x+xy^'=0 ?
The solution for y-x+xy^'=0 is y= x/2+(c_{1})/x