What is the tangent of f(x)=2(3x-8)^4-5x+6,\at x=3 ?

The tangent of f(x)=2(3x-8)^4-5x+6,\at x=3 is y=19x-64

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tangent of f(x)=2(3x-8)^4-5x+6,\at x=3

tangent of

f (x) = 2 (3 x - 8)^{4} - 5 x + 6, at x = 3

y = 19 x - 64

Solution steps

Find the tangent point:

(3, - 7)

Find the slope of

f (x) = 2 (3 x - 8)^{4} - 5 x + 6 : \frac{df ( x )}{d x} = 648 x^{3} - 5184 x^{2} + 13824 x - 12293

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 19

Find the line with slope m=

19

and passing through

(3, - 7) : y = 19 x - 64

y = 19 x - 64

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\frac{d}{d x} (10 e^{2 x})

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What is the tangent of f(x)=2(3x-8)^4-5x+6,\at x=3 ?
The tangent of f(x)=2(3x-8)^4-5x+6,\at x=3 is y=19x-64