What is (\partial)/(\partial x)(xy^7-x^2y) ?

The answer to (\partial)/(\partial x)(xy^7-x^2y) is y^7-2yx

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(\partial)/(\partial x)(xy^7-x^2y)

\frac{\partial}{\partial x} (x y^{7} - x^{2} y)

y^{7} - 2 y x

Solution steps

\frac{\partial}{\partial x} (x y^{7} - x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y^{7}) - \frac{\partial}{\partial x} (x^{2} y)

\frac{\partial}{\partial x} (x y^{7}) = y^{7}

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

= y^{7} - 2 y x

\frac{d}{d x} (10 e^{2 x})

\frac{d}{d x} (\frac{x ^{2}}{4 x + 1})

f (x) = \frac{2 - x ^{2}}{3 + x ^{2}}

n = 1 \sum \infty arctan (18 n)

n = 0 \sum \infty (1.1)^{n}

What is (\partial)/(\partial x)(xy^7-x^2y) ?
The answer to (\partial)/(\partial x)(xy^7-x^2y) is y^7-2yx